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adoni [48]
3 years ago
9

Find a formula for dy/dx if sin x + cos y + sec(xy) = 251

Mathematics
1 answer:
Lena [83]3 years ago
5 0

Answer:

\displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Trig Differentiation

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Implicit Differentiation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

sin(x) + cos(y) + sec(xy) = 251

<u>Step 2: Differentiate</u>

  1. [Implicit Differentiation] Trig Differentiation [Chain Rule]:                             \displaystyle cos(x) - sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = 0                      
  2. [Subtraction Property of Equality] Isolate  \displaystyle \frac{dy}{dx}  terms:                                     \displaystyle -sin(y)\frac{dy}{dx} + sec(xy)tan(xy) \cdot (y + x\frac{dy}{dx}) = -cos(x)
  3. [Distributive Property] Distribute sec(xy)tan(xy):                                            \displaystyle -sin(y)\frac{dy}{dx} + ysec(xy)tan(xy) + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x)
  4. [Subtraction Property of Equality] Isolate  \displaystyle \frac{dy}{dx}  terms:                                     \displaystyle -sin(y)\frac{dy}{dx} + xsec(xy)tan(xy)\frac{dy}{dx} = -cos(x) - ysec(xy)tan(xy)
  5. Factor out  \displaystyle \frac{dy}{dx}:                                                                                                   \displaystyle \frac{dy}{dx}[-sin(y) + xsec(xy)tan(xy)] = -cos(x) - ysec(xy)tan(xy)
  6. [Division Property of Equality] Isolate  \displaystyle \frac{dy}{dx}:                                                      \displaystyle \frac{dy}{dx} = \frac{-cos(x) - ysec(xy)tan(xy)}{-sin(y) + xsec(xy)tan(xy)}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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