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Alexeev081 [22]
3 years ago
7

Write the equation of the line pictured in standard form

Mathematics
1 answer:
Harman [31]3 years ago
5 0

Answer:

x+2y=4

Step-by-step explanation:

y=-1/2x+2 multiply both sides by 2

2y=-1x+4

2y+x=4 or x+2y=4 standard form

You might be interested in
Prove divisibility 45^45·15^15 by 75^30
Anuta_ua [19.1K]

Answer:

3^{75}

Step-by-step explanation:

We are asked to divide our given fraction: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(3*15)^{45}=3^{45}*15^{45}

75^{30}=(5*15)^{30}=5^{30}*15^{30}

Substituting these values in our division problem we will get,

\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}

\frac{3^{45}*15^{60}}{5^{30}*15^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{45}*15^{60-30}}{5^{30}}

\frac{3^{45}*15^{30}}{5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{3^{45}*(3*5)^{30}}{5^{30}}

\frac{3^{45}*3^{30}*5^{30}}{5^{30}}

Upon canceling out 5^{30} we will get,

3^{45}*3^{30}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

3^{45+30}

3^{75}

Therefore, our resulting quotient will be 3^{75}.

8 0
3 years ago
6x^2-4xy-15xy+10y^2 factor by grouping
PtichkaEL [24]
4 answers · Mathematics
Best Answer
We will need to split the middle term and use the grouping method. To do this multiply the coefficient of the first term (6) against the coefficient of the last term (10):

6 * 10 = 60
Factors of 60 = +-(1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60)

From the list of factors find two numbers that when added together give -19 and when multiplied together give 60. -15 and -4 added together give -19 and multiplied together give 60 so split the middle term by rewriting these values back into the expression:

6x^2 - 15xy - 4xy + 10y^2

Now use the grouping method, take out the highest common factor between the two sets of terms:

3x(2x - 5y) - 2y(2x - 5y)

Group the outside terms:

(3x - 2y)(2x - 5y)


Answers
6 = -3*-2
10 = 5*2
5*3+2*2=19
thus
(2y-3x)(5y-2x)
8 0
3 years ago
3x+4y-3z=4;5x-y+2z=3;x+2y-z=-2 Solving Systems in three variables​
Harlamova29_29 [7]

Answer:  x = 3, y = 1, z = 2

<u>Step-by-step explanation:</u>

EQ 1:   x  -   y  - z = 0

EQ 3:<u> -x + 2y + z =  1 </u>

                  y       = 1

EQ 2: 2x - 3y + 2z = 7  →  1(2x - 3y + 2z = 7)  →  2x - 3y + 2z = 7

EQ 3:  -x + 2y +  z = 1   → -2( -x + 2y +  z = 1)  → <u>-2x + 4y + 2z = 2</u>

                                                                                      y + 4z = 9

                                                                    y = 1  ⇒     1  + 4z = 9

                                                                                            4z = 8

                                                                                              z = 2

Input y = 1 and z = 2 into one of the equations to solve for x:

EQ 1: x - y - z = 0

        x - (1) - (2) = 0

        x - 3 = 0

        x = 3

Check:

EQ 2: 2x - 3y + 2z = 7

         2(3) - 3(1) + 2(2) = 7

          6    -  3    +  4    = 7

                3        +  4    = 7

                               7   =  7   \checkmark

6 0
3 years ago
Find the median first quarrile, third quartile, interquartile range, and an outliers for each set of data
Igoryamba
The outlier is 68

The median is 102
First quartile: 87
Third Quartile: 115
The interquartile range is 87-115
3 0
3 years ago
Harry took out a loan from the bank. The variable D models Harry's remaining debt (in dollars) t months after he took out the lo
tensa zangetsu [6.8K]

Answer:

700

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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