The student who traveled to states visited new states during a vacation. Does increasing the to change the median? If so, how?
1 answer:
Step-by-step explanation:
The exact question is as follows :
Given - The student who traveled to 3 states visited 6 new states during a vacation.
To find - Does increasing the 3 to 6 change the median? If so, how?
Proof -
Yes,
If we increase the 3 states to 6 states, it changes the median
Because
The median of the first 3 states is the middle state.
For example -
If we have 3 states X, Y, Z
Then the median is the state Y
Now,
The median of 6 states is the average of the 2 middle states.
For example -
If we have 6 states
X, Y, Z, U, V, W
Then
The median is not explicit.
Median is the average of the two middle states, Z and U.
And
Average of Z and U = half of the sum of Z and U.
i.e. (Z + U)/2.
And we can see that,
Median of 3 States is not equal to Median of 6 states
i.e. Y is not equal to (Z + U)/2.
So,
We can say that,
Increasing the state 3 to 6 changes the median.
You might be interested in
Answer:
The answer to your question is the second option
Step-by-step explanation:
Expression
Process
1.- Divide the fraction in numerator and denominator
a) Numerator
[(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸
b) Denominator
[(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶
2.- Simplify like terms
a) x⁻¹²x⁻³⁶ = x⁻⁴⁸
b) y⁻¹⁸y⁻¹⁸= y⁻³⁶
c) z⁻⁶
3.- Write the fraction
Answer:
We know that the ratio of length and breadth of a rectangular playground is 3:2
Then if the length is L, and the breadth is B, we have the relationship:
L = (3/2)*B
Outside this playground, we have a jogging track of 2m, then if we also consider the jogging track the length and breadth are:
L' = L + 2m
B' = B + 2m
The area is the product between the area and the breadth, then the area is:
A = B'*L'
A = (L + 2m)*(B + 2m)
And remember that L = (3/2)*B
Then we get:
A = ((3/2)*B + 2m)*(B + 2m)
And the area is 2816 m^2
Then we have:
A = ((3/2)*B + 2m)*(B + 2m) = 2816 m^2
Now we can solve the equation:
((3/2)*B + 2m)*(B + 2m) = 2816 m^2
(3/2)*B^2 + 3m*B + 2m*B + 4m^2 = 2816 m^2
(3/2)*B^2 + 5m*B = 2816 m^2 - 4m^2 = 2812m^2
Then we can write:
(3/2)*B^2 + 5m*B - 2812m^2 = 0
We can solve this if we use Bhaskara's formula:
One solution is negative, so we can discard that one, then we only take the positive:
B = (-5m + 130m)/3 = 41.67m
And L = (3/2)*B
L = (3/2)*40.7m = 62.5m
The breadth is 41.67 meters and the length is 62.5 meters.