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3 years ago

Cheyenne drove 3,000 miles in 75 hours. At this rate, how long will it take her to drive 4,000 miles?

1 answer:

8 0

First step=
we need to find time for i mile
which is
75/3000=1/40
then to find for 4000 miles we multiply that by 4000
which is 1/40x4000
cancel zeros
1/4x400
=100 hours for 4000 miles

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What represents 60=5 x 12?

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multiplication

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3 years ago

A landscaper is comparing the costs of potted plants from two nurseries. Nursery P charges $15 per plant plus a $50 delivery fee

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Answer:

The required number of plants is 10.

Step-by-step explanation:

Nursery P charges $15 per plant plus a $50 delivery fee on any order. Nursery Q charges $20 per plant and no delivery fee.

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2 years ago

Read 2 more answers

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

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3 years ago

One day , the tempeture ranged from a high of 20 degrease to a low of -25F. By how many degrees did the tempeture change?

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The temperature changed 45 degrees

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