The rectangular equation for given parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π is
which is an ellipse.
For given question,
We have been given a pair of parametric equations x = 2sin(t) and y = -3cos(t) on 0 ≤ t ≤ π.
We need to convert given parametric equations to a rectangular equation and sketch the curve.
Given parametric equations can be written as,
x/2 = sin(t) and y/(-3) = cos(t) on 0 ≤ t ≤ π.
We know that the trigonometric identity,
sin²t + cos²t = 1
⇒ (x/2)² + (- y/3)² = 1
⇒ 
This represents an ellipse with center (0, 0), major axis 18 units and minor axis 8 units.
The rectangular equation is 
The graph of the rectangular equation
is as shown below.
Therefore, the rectangular equation for given parametric equations x = 2sint and y = -3cost on 0 ≤ t ≤ π is
which is an ellipse.
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Answer:
y=21 and x=45
Step-by-step explanation:
Answer: Im pretty sure it would be 50
Step-by-step explanation:
500 divided by 10 equals 50
Answer:
<em>{ - 2 , 8 } </em>
Step-by-step explanation:
( x² - 6x ) = 2
4² = ( x² - 6x )
x² - 6x - 16 = 0
- 6 = - 8 + 2
- 16 = - 8 * 2
( x - 8 )( x + 2 ) = 0 ⇒
= - 2 ,
= 8
<em>{ - 2 , 8 }</em>
Divisible by 5 and 9 as 9x5=45 so that is the answer.........