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Volgvan
3 years ago
14

Andre drives a bike for 4 hours covering 160 km. Find the distance covered by him in 7 hours.

Mathematics
2 answers:
swat323 years ago
4 0

Answer:

I think is 280km :))))))

SpyIntel [72]3 years ago
3 0

Answer:

Andre covered 280km.

Step-by-step explanation:

I would say make a proportion:

?= distance covered

4 - 160

7 - ?

Solve: 7×160÷4=280.

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3 years ago
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Find all solutions in the interval [0,2π) of the equation.
Sauron [17]

Step-by-step explanation:

2sin(x)cos(x) - sin(x) + 2cos(x)-1= 0

<=> sinx( 2cosx -1) + ( 2cosx -1) =0

<=> (sinx +1) + ( 2cosx-1)=0

<=> sinx=-1 or cosx= 1/2

+) sinx=1 => x= pi/2 + k×2pi

+)cosx=1/2 => x= pi/3+ k×2pi or x=-pi/3 + k×2pi

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SpyIntel [72]

Answer:

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A factor is a number that is being multiplied.

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6 0
3 years ago
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A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

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A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

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The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
Which mean the same as 60%? Check all that apply
andrew-mc [135]

Answer:

a, c, d

Step-by-step explanation:

1. a: 3/5=0.6=60%

2. c: 0.60=60%

3. d: 6/10=0.6=60%

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3 years ago
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