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Volgvan
2 years ago
14

Andre drives a bike for 4 hours covering 160 km. Find the distance covered by him in 7 hours.

Mathematics
2 answers:
swat322 years ago
4 0

Answer:

I think is 280km :))))))

SpyIntel [72]2 years ago
3 0

Answer:

Andre covered 280km.

Step-by-step explanation:

I would say make a proportion:

?= distance covered

4 - 160

7 - ?

Solve: 7×160÷4=280.

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What is 1/4 + 1/4 + 1/4 =
Zepler [3.9K]

3/4 is the answer

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3 years ago
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Answer quick please.
olchik [2.2K]

5/2 = 2.5

4/16 = 0.25

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6 0
3 years ago
Right triangle QRS is pictured below.
sineoko [7]

Step-by-step explanation:

<u>Step 1:  List out all of the formulas for the trigonometric functions </u>

<em>sin(x) </em>= opposite/hypotenuse

<em>cos(x)</em> = adjacent/hypotenuse

<em>tan(x) </em>= opposite/adjacent

<u>Step 2:  Find the value of RS </u>

cos(31) = RS/24.8 NOT 24.8/RS

sin(31) = QS/24.8 NOT RS/24.8

sin(31) = QS/24.8 NOT 24.8/RS

cos(31) = RS/24.8 WHICH IS SAME AS RS/24.8

Answer: The correct length would be given from Option D, cos(31) = RS/24.8

3 0
3 years ago
Read 2 more answers
Suppose u · v = 0. Which vectors could represent u and v?
eduard

Answer: A. u = ⟨3, 4⟩ and v = ⟨4, –3⟩

Step-by-step explanation:

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5 0
3 years ago
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A single​ 6-sided die is rolled twice. The set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

Step-by-step explanation:

Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
3 years ago
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