Answer C
Step-by-step explanation: lol idk
Hello there! Given there are 70 employees after downsizing by 30%, let x equal the number of employees prior to the layoffs:
70 would have to be 70% of x.
To find what 70 is 70% of, we can multiply by 100 because 100 is the base denominator:
70 • 100 = 7,000
Given this equation, we can now divide our result by 70 to get what the amount of employees before the layoffs is:
7,000 divided by 70 gives us 100.
x = 100
Now, we can plug our answer in to see if it makes sense.
Does 70/100 represent 70%?
Yes, it does. 70/100 reduces to 7/10, and by adding 3/10 to our 70%, we get the initial amount of employees.
Your final answer: There were 100 employees prior to the layoffs. If you have any extra questions, let me know and I will gladly assist you.
I can’t see, make it clear
Answer:
Total Cost for Pretzels and juice is $9.
Step-by-step explanation:
Given:
Number of Bags of pretzels =3
Cost for each bag = $2.00
Total Cost of Pretzels is equal to product of Number of Bags of pretzels and Cost for each bag.
Framing in equation form we get;
Total Cost of Pretzels = 
Also Given:
Number of Bottle of Juice = 2
Price of each bottle = $1.5
Total Cost of Juice is equal to product of Number of Bottle of Juice and Price of each bottle.
Framing in equation form we get;
Total Cost of Juice = 
Total Cost of Pretzels and juice is equal to sum of Total Cost of Pretzels and Total Cost of Juice.
Total Cost of Pretzels and juice = Total Cost of Pretzels + Total Cost of Juice
Total Cost of Pretzels and juice = $6 + $3 =$9
Hence Total Cost for Pretzels and juice is $9.
Yes. That point is in the solution space.
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You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution