8. What do you believe: should husbands make decisions for their wives.
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Using the knowledge in computational language in LC-3 Assembly it is possible to write a code that replaces the value in R0 with its absolute value
<h3>Writting the code </h3>.ORIG x0200
START
AND R0, R0, #0 ; copy R0 to itself to set the condition codes based on R0;
; i.e performing addition operation with Zero option to set the flags
BRzp DONE ; if R0 is NON-NEGATIVE, skip the negation (already correct);
; Branch to DONE if number is poistive
NOT R0, R0 ; R0 is negative, so negate it i.e taking 2's complement
ADD R0, R0, #1 ; R0 = -R0 is performed successfully
DONE BR START
.END
See more about LC-3 Assembly at brainly.com/question/12978370
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Answer:
Here is the CoordTransform() function:
void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){
xValNew = (xVal + 1) * 2;
yValNew = (yVal + 1) * 2; }
The above method has four parameters xVal and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *
Here new variables are xValNew and yValNew and old is represented by xVal and yVal.
Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.
Explanation:
Here is the complete program:
#include <iostream>
using namespace std;
void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){
xValNew = (xVal + 1) * 2;
yValNew = (yVal + 1) * 2;}
int main()
{ int xValNew;
int yValNew;
int xValUser;
int yValUser;
cin >> xValUser;
cin >> yValUser;
CoordTransform(xValUser, yValUser, xValNew, yValNew);
cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;
return 0; }
The output is given in the attached screenshot
