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3 years ago

5th grade math. Correct answer will be marked brainliest.

Mathematics

2 answers:

myrzilka [38]3 years ago

8 0

Answer:

45.2 × 10⁰ = 45.2 (a⁰ = 1 )

45.2 × 10¹ = 452

45.2 × 10² = 4520

45.2 × 10³ = 45200

professor190 [17]3 years ago

3 0

Answer:

My siblings ALWAYS have think central, its annoying.

Step-by-step explanation:

1. 45.2

2. 452

3. 4520

4. 45200

Its like moving the place value and adding a 0. I used Desmos Scientific Calculator to check my answers.

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The larger of two consecutive odd integers is four less than three times the smallest integer. Find the two integers.

ElenaW [278]

Answer: -1 and 1

Step-by-step explanation:

Let the first integer be x and the second x +2 , clearly, the larger is x + 2.

From the statement given

x + 2 = 3x + 4

x - 3x = 4 - 2

-2x = 2

x = -1

The second integer is -1 + 2 = 1

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4 years ago

Daredevil Danny takes a practice jump as shown on the graph below. Complete the steps to determine the equation for the paraboli

Tju [1.3M]

Answer:

Step 2:

Part A

f(x) = a(x-h)^2 +k

Part B

I'm not really sure about this part

Part C

f(x)=-12/25(x-25)^2+32

Step 3:

Part A

y = ax^2 + bx + c

Part B

f(x) = -12/25(x - 25)^2 + 32

Part C

a = -12/25

b = 0

c = 32

Step-by-step explanation:

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4 years ago

What is the difference between exponent form and expanded form (repeated multiplication)?

Inga [223]

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3 years ago

What is the solution to this equation 8 - 2x + 6x = 24

san4es73 [151]

x = 4

First you combine like terms:

8 + 4x = 24

Then solve:

4x = 24 - 8

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4 0

3 years ago

Read 2 more answers

Let n be a natural number. Show that 3 | n3 −n

Vladimir [108]

Let $n=1$ . Then $n^3-n=1^3-1=0$ . By convention, every non-zero integer $n$ divides 0, so $3\vert n^3-n$ .

Suppose this relation holds for $n=k$ , i.e. $3\vert k^3-k$ . We then hope to show it must also hold for $n=k+1$ .

You have

$(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)$

We assumed that $3\vert k^3-k$ , and it's clear that $3\vert 3(k^2+k)$ because $3(k^2+k)$ is a multiple of 3. This means the remainder upon divides $(k+1)^3-(k+1)$ must be 0, and therefore the relation holds for $n=k+1$ . This proves the statement.

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3 years ago