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tino4ka555 [31]
3 years ago
5

8) Jalyn purchased three different sized drinks. The large was twice as much

Mathematics
1 answer:
puteri [66]3 years ago
8 0

Answer:<em>M</em><em>A</em><em>R</em><em>K</em><em> </em><em>M</em><em>E</em><em> </em><em>A</em><em>S</em><em> </em><em>B</em><em>R</em><em>A</em><em>I</em><em>N</em><em>L</em><em>I</em><em>E</em><em>S</em><em>T</em>

MEGA Drink = $10+2x

LARGE Drink = 2x

MEDIUM Drink = x

hence, we conclude that

($10+2x) + 2x + x = $45

$10+2x + 2x + x =$ 45

5x + $10 = $45

5x = $45-$10

5x = $35

x = 35÷5

x = 7

MEGA DRINK = (10+2X)

10+2×7

10+14

24

LARGE DRINK = 2X

2×7 = 14

MEDIUM DRINK = X

7

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Brilliant_brown [7]

Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.

For example, if you have

... u'' + a·u' + b·u = f

you can define u1 = u, u2 = u' and now you have the system

... (u2)' + a·u2 + b·u1 = f

... (u1)' = u2

Rearranging, this is

... (u1)' = u2

... (u2)' = f - a·u2 - b·u1

ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.

7 0
4 years ago
I need help on this hhhhhhhh​
Anon25 [30]

\huge\text{Hey there!}

\mathsf{\dfrac{10^{15}}{10^4}}

\mathsf{10^{15}}\\\mathsf{=10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times 10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 1,000,000,000,000,000}}

\mathsf{\dfrac{\bold{1,000,000,000,000,000}}{10^4}}

\mathsf{10^4}\\\mathsf{= 10\times10\times10\times10}\\\mathsf{10\times10=\bf 100}\\\mathsf{100\times100}\\\mathsf{= \boxed{\bf 10,000}}

\mathsf{\dfrac{1,000,000,000,000,000}{\bf 10,000}}

\mathsf{\dfrac{1,000,000,000,000,000}{10,000}}\\\\\mathsf{= 1,000,000,000,000,000\div 10,000}\\\\\mathsf{= \boxed{\bf 100,000,000,000}}

\mathsf{10^{11}}\\\mathsf{10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 100,000,000,000}}

\mathsf{100,000,000,000= 100,000,000,000= 10^{11}}

\boxed{\boxed{\large\text{Answer: BASICALLY }\mathsf{\dfrac{10^1^5}{10^4}\large\text{ is EQUAL to or EQUIVALENT to}}}}\\\boxed{\boxed{\mathsf{10^{11}}\large\text{ because they both give you the result of \bf 100,000,000,000}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
3 years ago
Most new buildings are required to have a ramp for the handicapped that has a maximum vertical rise of 11 feet for every 132 fee
Komok [63]

Answer:

11/132 = 1/12

Step-by-step explanation:

just put the rise over the run and simplify

8 0
3 years ago
The spray from a sprinkler reaches 21 feet from the sprinkler and creates a circle as it spins. What is the circumference of the
lina2011 [118]

C=πd

r=21

d=42

C=132 ft, and D is your final answer. Hope it help!

4 0
3 years ago
What is 60 + 9.000000000
adell [148]

Answer:

69

Step-by-step explanation:

8 0
3 years ago
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