Answer: Variables
F and C are placeholders for numbers. They are called variables because they are allowed to vary, or change. If you change C then it affects F, and vice versa. If the values for the placeholders is not allowed to change, yet it holds a number, then it is considered a constant. In this case, we don't have constants or else the formula isn't too useful.
The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
<h3>What is the area of the kite figure?</h3>
The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.

Here, p and q are the diagonals of the kite.
The length of the first diagonal of the kite figure is,
p=6+15
p=21 cm
The length of the second diagonal of the kite figure is,
q=8+8
q=16 cm
Thus, the area of kite figure is:

Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
Learn more about the area of kite here;
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Answer:
1.85
Step-by-step explanation:
1.75-0.5+0.6= 1.85 or 1 17/20
Answer:
None of them
Step-by-step explanation:
y=-x-5 => slope=-1
A. slope =-2/3
B. slope =-3/2
C. slope = 2/3
D. slope = 2/3
None of slope of the choices is -1
Answer:
25 in x 15 in
Step-by-step explanation:
Given:
- Length = 3/5 the width
- Area = 375 in²
Let width = 
Therefore, length = 3/5 
First create an equation for the area of the picture based on the given information for its width and length:

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for
to find the width of the enlarged picture:

Therefore, the width of the enlarged picture is 25 in.
Substitute the found value of
into the expression for length to find the length of the enlarged picture:

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.