Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
Answer:
y ≈ 2.5
Step-by-step explanation:
Using the Sine rule in Δ XYZ
= 
, substitute values
= 
( cross- multiply )
y sin50° = 2 sin75° ( divide both sides by sin50° )
y = 
≈ 2.5 ( to the nearest tenth )
C since it is a positive 1640 and that is what you are looking for
Answer:
B
Step-by-step explanation:
B is in Quadrant III.
B is the answer.
Answer:
y approaches negative infinty
