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ICE Princess25 [194]
3 years ago
7

H/2 + 21 - k if h=20 and k=89

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

-58

Step-by-step explanation:

(20/2) + 21 - 89

first we will do brackets than addition and at the end we will do subtraction, so than  we will get -58

I hope this helps a little bit.

andrezito [222]3 years ago
5 0

23-89=66/2=33

Step-by-step explanation:

LOOK UP!

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Dave's age in 4 years is 18. Write an equation that represents Dave's age in 4 years.
julsineya [31]
This equation might be x + 4 =18

3 0
4 years ago
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The base lengths of a trapezoidal coffee table are 6 feet and 8 feet. The height is 5 feet. What is the area of the coffee table
den301095 [7]

A = (a+b)h/2

A = 6

B = 8

H = 5

A = (6+8)5/2

A = 14(2.5)

A = 35

The area of the coffee table is 35 sq. feet.

7 0
4 years ago
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Please help!! I'm probably gonna be spamming sooo​
Genrish500 [490]

Answer:

12π

is the correct answer

3 0
3 years ago
Clare analyzes oil prices in her economics class. She finds that the mean oil price between 1988 and 2002 is $27 per barrel with
avanturin [10]

Answer:

Option 2: 1.5 is the correct answer.

Step-by-step explanation:

Given information is:

Mean = μ = $27

SD = σ = $5.50

A z-score simply tells us how far a selected data value from the mean is.

Z-score is denoted by z and is given by the formula:

z = \frac{x-mean}{SD}

Let x = $35.25

Putting the values of mean and SD we get,

z = \frac{35.25-27}{5.50}\\z = \frac{8.25}{5.50}\\z =1.5

The value of z-score for a price of $35.25 per barrel is 1.5

Hence,

Option 2: 1.5 is the correct answer.

7 0
3 years ago
The gas mileage for a certain model of car is known to have a standard deviation of 6 mi/gallon. A simple random sample of 36 ca
xxTIMURxx [149]

The 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Confidence intervals are defined as a range of values with a known chance that a parameter's value falls inside them.

The confidence interval of statistical data is computed using the formula:

(\overline{x} - Z\frac{\sigma }{n},\overline{x} + Z\frac{\sigma }{n})

where \overline{x} is the mean, Z is the Z-score corresponding to the confidence interval, σ is the standard deviation, and n is the sample size.

In the question, the sample size (n) = 36, the mean of the sample (\overline{x}) = 28.4 mi/gallon, the standard deviation (σ) = 6 mi/gallon.

The confidence interval given to us is 98%.

Z-score corresponding to this (Z) = 2.33.

Thus, the confidence interval can be calculated as:

(28.4 - 2.33{6/√36},28.4 + 2.33{6/√36})

= (28.4 - 2.33,28.4 + 2.33)

= (26.07,30.73).

Thus, the 98% confidence interval for the mean gas mileage for this car model is (26.07,30.73).

Learn more about constructing confidence intervals at

brainly.com/question/17030704

#SPJ4

5 0
2 years ago
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