1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
4 years ago
8

4 loads of stone weigh 2/3 ton. Find the weight of 1 load of stone.

Mathematics
2 answers:
lana66690 [7]4 years ago
8 0
4 loads of stone ... 2/3 ton
1 load of stone ... x ton = ?

If you would like to know the weight of 1 load of stone, you can calculate this using the following steps:

4 * x = 2/3 * 1
4 * x = 2/3       /4
x = 2/3 / 4
x = 2/12 = 1/6 ton

The correct result would be 1/6 ton.
Otrada [13]4 years ago
3 0
1 ton = 2000 pounds
2000 ÷ 3 = 666.6 (we'll round it to 667)
667 × 2 = 1334 pounds = 4 loads
1334 ÷ 4 = 333.5 pounds = 1 load of stone
You might be interested in
Under a dilation, triangle A(2,2), B(2,0), C(4,0) becomes A'(8,8), B'(8,0), C'(16,0).
PIT_PIT [208]

Answer:

we are going to times the sides by four

3 0
2 years ago
Using the formula F=9/5C+32, find C when F= 75.
den301095 [7]

Answer:

DIVIDING 9 AND 5 = 23.8

9/5 FRACTION = 0.04

Step-by-step explanation:

If 9/5 means 9 divided by 5

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5 = 1.8

1.8C = 43

1.8C/1.8 = 4

If 9/5 means 9/5ths fraction

FLIP THE EQUATION

9/5C + 32 = 75

9/5C + 32 - 32 = 75 -32

9/5C = 43

9/5C / 9/5 = 43 / 9/5

C = 0.04

Hope this helps i thought 9/5 was 9 divide by 5. If it was 9/5 as a fraction i also made that equation too.

7 0
3 years ago
HELP ASAP PLEASE!!! Explain how you will benefit most from improving your math skills.
RideAnS [48]

Answer:

Some of the most lucrative jobs are all about math. Most engineering fields are all about sharp math skills, whether it’s civil and mechanical or software engineering. Working in finance also obviously involves a lot of math, and what better way to make money than working in the field that’s all about money? You can also become a statistician or actuary; it’s not easy to find good statisticians, despite the need for them. If you want to earn good money, then you do need good math skills.Then again, you could use math in life anyway.

Step-by-step explanation:

7 0
3 years ago
elect all that apply. A card is randomly drawn from a deck of cards. (There are 52 cards in a deck, with 13 cards of each suit.)
raketka [301]
If the original experiment trial was 100 draws the 
A. True - Experimental probability of drawing a club is 32%
B. True - Theoretical probability of drawing a diamond is 25%
C. True - Experimental probability of drawing a spade 90 times out of 500 trials
6 0
3 years ago
(4x + 3) + (-2x + 4)
WITCHER [35]

Answer:

<h2>(4x + 3) + (-2x + 4) = 2x + 7</h2>

Step-by-step explanation:

(4x + 3) + (-2x + 4)

= 4x + 3 - 2x + 4         <em>combine like terms</em>

= (4x - 2x) + (3 + 4)

= 2x + 7

4 0
3 years ago
Read 2 more answers
Other questions:
  • 250 people went to a “couples party” party at 9am. If 70 people left at 11pm how many couples remained at the party?
    8·1 answer
  • Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of y=4x^2+5x-1
    10·1 answer
  • Which is the largest multiple of five that lies in the solution set for 19
    12·1 answer
  • What does it mean for a product of factors to be expressed using exponents
    15·1 answer
  • the school chorus has 52 students which represents 26% of the 7th graders how many students are in the 7th grade
    6·2 answers
  • I need help finding the weather it is continuity or not
    15·1 answer
  • Last year the 6th grade had 350 students. This year the number Increased 36%. How many students are in this year's 6th-grade cla
    12·1 answer
  • Which inequality is NOT true if y = -5?
    14·2 answers
  • Use pemdas 4 + (2 x 12) - 3^2
    6·2 answers
  • Prove that SinA×tanA/1-CosA=1+secA​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!