<img src="https://tex.z-dn.net/?f=15%5E%7B-4%7D" id="TexFormula1" title="15^{-4}" alt="15^{-4}" align="absmiddle" class="latex-f

Black_prince [1.1K]

2 years ago

ormula"> ÷ $(-3)^{0}$ · $(\frac{1}{5} )^{-4}$

Mathematics

1 answer:

Anit [1.1K]2 years ago

5 0

Answer:

1/81

Step-by-step explanation:

You might be interested in

What is -3/4 + (-3/14) Give your answer as a reduced fraction

Advocard [28]

Answer:

- $\frac{27}{28}$

Step-by-step explanation:

hope this was the answer you were looking for.

4 0

3 years ago

1. Alexia started babysitting when she was in high school. She has built a reputation for herself and has become popular among t

Alinara [238K]

$10+$5=15
$75/$15=5
Hours = 5

Is this what you were looking for?

7 0

3 years ago

I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem i

Anna [14]

We know that the law of sines states that:

$\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}$

For simplicity, let:

$\beta=m\angle A_1BC$

In triangle A1BC this leads to:

$\begin{gathered} \frac{\sin31}{5}=\frac{\sin\beta}{6} \\ \sin\beta=\frac{6}{5}\sin31 \\ \beta=\sin^{-1}(\frac{6}{5}\sin31) \\ \beta=38.174 \end{gathered}$

Therefore:

$m\angle A_1BC=38.174$

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:

$m\angle CA_2B=180-38.174=141.826$

8 0

1 year ago

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form.

Paladinen [302]

Answer:

gradient =y2-y1÷x2-x1

=10-5÷2-(-3)

y-y1=m(x-x1)

y-5=1(x-(-3))

y=x+2

7 0

2 years ago

Paper clips cost $2.20 per 1000. How much would I need to pay for 4,500

dem82 [27]

Answer:

2.20 per 1000 so it's gonna be $2.20/1000 per 1. So 4500 take $2.20/1000*4500=...

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers