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3 years ago

Evaluate x−y when x=23 and y=−13

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

The equation would turn out as 23--13

But when there are two negatives, it turns into a positive, creating the equation of 23+13

Then you add to equal 36.

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Which graph below has an vertical shift of 2

Lelechka [254]

Answer:

b. y=sin(x)+2

Step-by-step explanation:

A vertical shift moves the graph up and down on the y axis. In order to move the graph up 2 units, 2 must be added to the entirety of sin(x). Vertical shifts always appear last in the equation and are always added or subtracted.

5 0

3 years ago

Help me please...thank you

Ahat [919]

I think the answer is 5! I hope this helps!!

6 0

3 years ago

fran drank 19/20 liter of juice how many quarts of juice did she drink (1 L =1.06qt). set up a proportion and solve using means

gayaneshka [121]

Given :

Fran drank 19/20 liter of juice.

1 L = 1.06 qt.

To Find :

How many quarts of juice did she drink.

Solution :

It is given that :

$1 \ L=1.06\ qt\\\\1=\dfrac{1.06\ qt}{L}$

Now, amount of water he drink :

$\dfrac{19}{20}\times 1 \ L\\\\\dfrac{19}{20}\times 1.06\ \dfrac{qt}{L}\times L\\\\\dfrac{19}{20}\times 1.6 \ qt\\\\1.52\ qt$

Hence, this is the required solution.

6 0

3 years ago

What is greater one hundred fifty two thousand or five million

Olin [163]

One hundred fifty two thousands is 152.000
and 5 million is 5000000

so from this result that 5 million is greater

6 0

3 years ago

The sum of the first number cubed and the second number is 500 and the product is a maximum.

soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

$x^3+w=500$

We can then express y as:

$w=500-x^3$

We can express their product as:

$x(500-x^3)=500x-x^4$

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

$\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}$

Then we solve for the value of x where f'(x) = 0.

$\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}$

Then we use x = 5 to solve for the second number, w.

$\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}$

Therefore, the two numbers are 5 and 375.

3 0

1 year ago