Ask question

Ask question

All categories

IrinaVladis [17]

3 years ago

11

Write and algebraic expression , Twice a number n

1 answer:

kenny6666 [7]3 years ago

4 0

Answer:

2(n) or 2n

Step-by-step explanation:

.................

You might be interested in

For what value of x is the rational expression below equal to zero

Elena L [17]

X = 2

S P A C E F I L L E R L O L

8 0

3 years ago

About 2% of the population has a particular genetic mutation. 500 people are randomly selected.

S_A_V [24]

The standard deviation for the number of people with the genetic mutation in such groups is 3.1305.

<h3>Standard Deviation</h3>

In statistics, the standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the values tend to be close to the mean of the set, while a high standard deviation indicates that the values are spread out over a wider range.

Let X be the number of people with genetic mutation is a group of 500,

The formula of standard deviation is given as

$SD=\sqrt{n*p(1-p)} \\SD=\sqrt{500*0.02*0.98} \\SD=3.1305$

The standard deviation of the given sample is 3.1305

Learn more on standard deviation here;

brainly.com/question/28290366

#SPJ1

4 0

2 years ago

J(h - 9) + 2; use h=9, and j = 8

shepuryov [24]

It should be -6

8(8-9)+2

Step-by-step explanation:

3 0

3 years ago

10 pounds of soil are needed to

Wewaii [24]

Answer:

40/3

Step-by-step explanation:

w = weight of soil needed

f = number of flower beds

a = constant value

w = a * f

<em>substitute</em>

10 = 6a

<em>simplify</em>

5/3 = a

w = (5/3)f

<em>plug in 8</em>

w = (5/3)(8)

<em>simplify</em>

w = 40/3

3 0

4 years ago

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

3 years ago