Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
12,789 chocolate
9,324 Cookie Dough
10,402 Peanut Butter Cones
13,788 Vanilla
46,303 in total
R - 10/3 + 1/2 = -11/6...if u multiply everything by the common denominator 6, it will get rid of the fractions.
(6)r - 6(10/3) + 6(1/2) = 6(-11/6)
6r - 60/3 + 6/2 = - 66/6...simplify
6r - 20 + 3 = - 11
6r - 17 = -11
6r = -11 + 17
6r = 6
r = 6/6
r = 1 <===
