All categories

3 years ago

Please helppppp

Mathematics

1 answer:

maksim [4K]3 years ago

6 0

The answer for this equation is q=5

You might be interested in

Function R gives the amount of rain measured by a rain gauge hours since it started raining. The amount of rain is measured in m

vladimir1956 [14]

Answer:

R(3) means that it has rained 3 millimeter and R(0.5)=14 means in 14 hours it has rained half a millimeter.

Step-by-step explanation:

5 0

3 years ago

A swearer cost $20 but the price was reduced to $ 12 what was the price after the price was reduced

bixtya [17]

Answer:

$20-$12=

Step-by-step explanation:

20-12=8

5 0

3 years ago

PLEASE ANSWER I REALLY NEED HELP ON THIS TEST

marshall27 [118]

Answer:

Step-by-step explanation:

beacause if you try to multiple 4x7.5 divided by 2 try it

6 0

3 years ago

F. one die is rolled 3 times. what is the chance of getting no 2's?

aniked [119]

6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions

6 0

3 years ago

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values

Slav-nsk [51]

Answer:

Systolic on right

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

$CV= \frac{\sigma}{\mu}$

And the best estimator is $\hat {CV} =\frac{s}{\bar x}$

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

$s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}$

For this case we have the following values:

$\bar x = 127.5, s= 18.68$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

For this case we have the following values:

$\bar x = 74.2 s= 12.65$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0

3 years ago