Answer:
Step-by-step explanation:
Let the three consecutive integers be x, x + 2 and x + 4
<u>So, the given condition is:</u>
x + x + 2 + x + 4 = 129
3x + 6 = 129
Subtract 6 to both sides
3x = 129 - 6
3x = 123
Divide 3 to both sides
x = 123/3
x = 41
<u>So, the integers are:</u>
x = 41
x + 2 = 41 + 2 = 43
x + 4 = 41 + 4 = 45
Hope this helped!
<h3>~AH1807</h3>
Total possibilities would be:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
You want 5 on at-least one, so mark 5th column & 5th raw.
There are 6 in both lines with 1 common = (5,5)
In short, Your Answer would be 11
Hope this helps!
X = 18 - 1/2 the answer is 18 of x/18
Answer:
The most tables she can have is 4 tables.
Step-by-step explanation:
To find how many tables she can have, you need to know the GCF between the two numbers, 12 and 20.
12: 1, 2, 3, <u>4</u>, 6, 12
20: 1, 2, <u>4</u>, 5, 10, 20
As you can see, the GCF is 4.
So, the most tables she can have is 4 tables.