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2 years ago

Let f(x) = -2x + 7 and g(x) = -6x + 3. Find fog and state its domain.

Mathematics

1 answer:

kondaur [170]2 years ago

4 0

Answer:

y=12x-39

Step-by-step explanation:

it's linear equation so the domain is real number

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Algebra question please helppp

mylen [45]

Step-by-step explanation:

if u need a clearer photo please tell me

5 0

2 years ago

5) Find the distance between -9 and 12 on a number line.

kati45 [8]

Answer: Hope this helps!!!

Step-by-step explanation:Absolute Value: You need to find how far away both numbers are from zero, then add these values together to see how far apart these numbers. The absolute value of nine, |-9| is 9, and |12| is 12. This means that the nine is nine spots away from zero, and twelve is twelve spots from zero. This means that the numbers are 20 units from each other.

Distance -9 is from 12 You need to find how much of an increase from nine you need to reach the twelve. So -9 + ? = 12. What number can you add to equal twelve? You can add 20 to make the equation true. (? = 20) The distance from -9 to 12 is a positive 20.

Distance from 12 to -9 This is similar to the previous example. What number can you insert to make the 12 equal the negative nine? 12 - ? = -9. The number would be -20, which means that 12 is 20 spots away from the negative nine, as it took at negative twenty to get us to the negative nine.

3 0

1 year ago

Mandy runs 4 km in 18 min. she plans to run in a 15 km race. how long will it take her to complete the race?

kompoz [17]

It will take Mandy an hour, seven minutes, and thirty seconds to complete the race.

(67 minutes and 30 seconds)

I hope my answer helped!

6 0

2 years ago

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

1 year ago

Solve this system of linear equations. separate the x- and y- values with a coma. -12x=-75-11y

ycow [4]

Solve the following system:
{-12 x = -11 y - 75 | (equation 1)
{-5 x = -11 y - 89 | (equation 2)
Express the system in standard form:
{-(12 x) + 11 y = -75 | (equation 1)
{-(5 x) + 11 y = -89 | (equation 2)
Subtract 5/12 × (equation 1) from equation 2:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+(77 y)/12 = (-231)/4 | (equation 2)
Multiply equation 2 by 12/77:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+y = -9 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{-(12 x)+0 y = 24 | (equation 1)
{0 x+y = -9 | (equation 2)

Divide equation 1 by -12:
{x+0 y = -2 | (equation 1)
{0 x+y = -9 | (equation 2)
Collect results:
Answer: {x = -2 {y = -9

please note that the parentheses "{" should span over both equations but the editor doesn't allow that so I should it on both line, See attached example.

4 0

2 years ago