Answer:
the sequence begins as {4, 7, ... }
Step-by-step explanation:
a(n) = 3n + 1
The first term is a(1) = 3(1) + 1 = 4, and
the second term is a(s) = 3(2) + 1 = 7
So the sequence begins as {4, 7, ... }
Solution: 1. The mean is given below:

Where:
is the frequency
is the value


Therefore, the mean = 2.4
2. The mean is given below:



I am not understanding why your teacher 14.3 is wrong. Please check whether the weight of 4 pumpkins is correct or not.
3. We are given that on average 5 passengers will board the bus at each of the 6 stops.
Let x be the number of passengers board the bus at the sixth stop.
Therefore, the average is:




Therefore, 7 passengers need to board the bus at the sixth stop for Leah's prediction to be true.
Using the relation of velocity, distance and time, it is found that 35 represents Michelle's velocity.
-----------------------------
Velocity is <u>distance divided by time</u>, then:

Kevin drove for 3.25 hours, thus
. The distance drove by Kevin is:


Michelle drove for 1.5 hours, thus
. The distance drove by Michelle is:


The total distance is:


Comparing to the expression:

We get that 42 is Kevin's speed and 35 is Michelle's speed.
A similar problem is given at brainly.com/question/24316569
Answer:
a
The 95% confidence interval is
b
The result obtained does not contradict expectation
Step-by-step explanation:
From the question we are told that
The number of green peas is k = 438
The number of yellow peas is u = 173
Generally the sample size is mathematically represented as

=>
=> 
Generally the sample proportion for yellow peas is

=> 
=> 
From the question we are told the confidence level is 95% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
From the question we are told that it was expected that 25% of the offspring peas will be yellow
Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so it means that the result obtained does not contradict expectation