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mihalych1998 [28]
3 years ago
14

PLS HELP PLS HELP PLS HELP PLS HELP PLS HELP I BEG U PLS BOTH QUESTIONS PLS

Mathematics
2 answers:
STatiana [176]3 years ago
6 0

Answer:14 is obtuse

15 is A

Step-by-step explanation:

For 14 the only remaining angle is over 90

For 15 the first triangle has all same side and angle measures

second triangle has 2 equal side measures

and third has none

Naddik [55]3 years ago
3 0

Answer:

1: Obtuse

2: A

Step-by-step explanation:

One angle is 57° and another is 12°. If we add them, we get 69. Subtract 69 from 180 to get missing angle: 180-69=111

the missing angle is 111°. We know this is not a right triangle because those have a 90° angle. Since one angle is bigger than 90 (111°), the triangle is obtuse.

For the second one, we see that the first triangle is equal on all sides, so it is equilateral. The second triangle has just two equal sides, so it is isosceles. The thrid one is different side length on all of them, so it is scalene. the answer is A.

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PLEASE ANSWER the most understandable will get brainliest
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Answer:

I think it should be the 1st one

Step-by-step explanation:

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4 0
3 years ago
Which of those is an example of numerical data ? A. Average speed b. Type of pet C. Favorite car d.home state
garri49 [273]
Average speed the others are categorical.
7 0
3 years ago
What is this 1/4 - (-3/4)= in math
Blababa [14]

Answer:

4/4 = 1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
3 years ago
12% of 72 is what number?
xxTIMURxx [149]
I hope this helps you ?.12%=72 ?.12=72.100 ?=6.100 ?=600
5 0
3 years ago
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