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telo118 [61]
3 years ago
14

Consider the following equation.

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0
The solution would be:

x=1.54
y=7.08
Fudgin [204]3 years ago
8 0

it has to be a fraction plz help

x= ?

a. 7/4

b. 27/16

c. 13/8

d. 25/16

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Express p in terms of q if
Irina-Kira [14]

p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)

q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}

8 0
2 years ago
Prove that the two circles shown are similar
andrezito [222]
Zoom factor will be the number to prove they’re the same
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3 years ago
For which interval is the function constant?
andreev551 [17]

Answer:

Option D (2, 6)

Step-by-step explanation:

As shown in the graph function has four intervals on which graph is plotted.

1). From the graph we can see in the interval -10 ≤ x ≤ 0 graph is increasing.

2). From 0 ≤ x ≤ 2 function is decreasing.

3). Between 2 ≤ x ≤ 6 function is constant.

4). And for x ≥ 6 function is increasing.

Therefore interval in which the function is constant is (2, 6).

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:


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