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IceJOKER [234]
3 years ago
15

How much heat energy is needed to raise the temperature of 2.0 kg of concrete from 10c to 30c

Physics
1 answer:
kompoz [17]3 years ago
3 0
50 because read step by step explanation
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What is the most common form of carbon? How is carbon-14 different?
adelina 88 [10]

Answer:

most common form of carbon is graphite and the other is diamond

7 0
3 years ago
What is the answer please help me!
Juliette [100K]

Answer:

The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground

Explanation:

We know that the earth's center attracts everything towards its center with an acceleration of 9.8 m/s² so it simply means that the change in velocity must occur to produce acceleration. When the ball comes towards the earth, its speed  continuously increases and it is at maximum level when it is about to hit the ground so this is the point where gravitational force is maximum.

I hope this helps ^_^

6 0
3 years ago
7. A neutron at rest decays (breaks apart) into a proton and an electron. Energy is released in the decay, in the form of kineti
kondaur [170]

Answer:

The fraction of the total energy goes into kinetic energy of proton is 5.44 \times 10^{-4}

Explanation:

Given:

Mass of proton m_{p} = 1836 m_{e}

Mass of electron m_{e} = 9.1 \times 10^{-31} kg

Here neutron at rest decays into proton and electron

   n_{1} ^{0}  ⇄ P_{1} ^{1} + e_{0} ^{-1} + Q

Where Q = energy released

The Q value of this reaction is given by

    Q = (\frac{m_{p} +m _{e} }{m_{e} } ) K

Where K = kinetic energy of reaction

Here we need to find fraction of the total energy released goes into the kinetic energy of the proton

   \frac{K}{Q}  = \frac{m_{e} }{m_{p} + m_{e}  }

   \frac{K}{Q} = (\frac{m_{e} }{1836m_{e} + m_{e}  } )

   \frac{K}{Q} = \frac{1}{1837}

   \frac{K}{Q} = 5.44 \times 10^{-4}

Therefore, the fraction of the total energy goes into kinetic energy of proton is 5.44 \times 10^{-4}

6 0
3 years ago
A helicopter descends from a height of 600 m with uniform negative acceleration, reaching the ground at rest in 5.00 minutes. de
uranmaximum [27]
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.

Let a =  the acceleration of descent., m/s².
Let u =  initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u,  v, and a are measured as positive upward.

Then
 u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a                  (1)

Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600       (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²

From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s

Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.

3 0
3 years ago
A space shuttle is traveling at 20,000 m/sec. At (T)ime = 5 sec, the rocket thrusters are turned on. The shuttle accelerates to
OLga [1]

Answer:

Wow I hope to never have to learn this

Explanation:

6 0
3 years ago
Read 2 more answers
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