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fgiga [73]
3 years ago
9

A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains

in static equilibrium. What is the mass of the meterstick
Physics
2 answers:
Vikki [24]3 years ago
6 0
Hey i dont have an answer but i need the points for finals today. Thank you
nordsb [41]3 years ago
3 0
I don’t know the answer sorry I need points
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A 1.0-kg block and a 2.0-kg block are pressed together on a horizontal frictionless surface with a compressed very light spring
egoroff_w [7]

Answer:

4. both blocks will both have the same amount of kinetic energy.

Explanation:

When the blocks are released free from the compression force, the spring exerts equal and opposite force on each block but the block with heavier (double) mass will attain slower ( half ) speed as compared to the lighter block according to the law of inertia. This works in synchronization to energy conservation.

Spring force is given as:

F=k.\Delta x

where: \Delta x= length of compression in the spring

<u>We know kinetic energy is given by:</u>

KE=\frac{1}{2} m.v^2

Hence the kinetic energy of both the blocks is equal when they are released to move free.

8 0
4 years ago
What has alternating electric and magnetic fields that travel in the form of a wave?
anzhelika [568]

Electromagnetic radiation...

7 0
3 years ago
A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 50 m. In this proble
Vadim26 [7]

Answer:

The velocity of the camera is 33.11 m/s.

Explanation:

Given that,

Speed = 10.8 m/s

Altitude = 50 m

Suppose determine the velocity of the camera just before it hits the ground?

We need to calculate the velocity of the camera

Using equation of motion

v^2=u^2+2gs

Where, v = final velocity of camera

u = initial speed of camera

s = distance

Put the value into the formula

v^2=(-10.8)^2+2\times(-9.8)\times(-50)

v=\sqrt{1096.64}

v=33.11\ m/s

The direction will be downward so it is the negative velocity.

Hence, The velocity of the camera is 33.11 m/s.

8 0
3 years ago
A roller-coaster car moves 172 ft horizontally and then rises 115 ft at an angle of 31.0° above the horizontal. it next travels
lianna [129]

172 + 115 cos 31 +115 cos 48 horizontally

115 sin 31 - 115 sin 48  vertically

possibly need some drawing

4 0
3 years ago
When you whirl a can at the end of a string in a circular path, what is the direction of the force that acts on the can
andreyandreev [35.5K]

Answer:

Toward the centre of the circular path

Explanation:

The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).

In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by

F=m\frac{v^2}{r}

where m is the mass of the object, v its tangential speed, r the radius of the trajectory. This force always points towards the centre of the circular path.

3 0
3 years ago
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