If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
y =0
Step-by-step explanation:
From the equation;
8³ × 8⁻⁵×8^y = 8⁻²= 1/8²
From the laws of indices;
aⁿ×aⁿ = a^2n
Therefore;
8³ × 8⁻⁵×8^y = 8^(3+-5+y)
8^(-2+y) = 8^-2 ; but the bases are the same and thus the exponents are the same;
-2 + y = -2
y = 0
Answer:
30cm x 72 cm
Step-by-step explanation:
The perimeter is the measurements of all sides added together. Let's start by dividing the perimeter by 2, so we have the sum of the length and width. This gives us 102cm. Let's call the width <em>x</em>, and the length <em>y</em>. We know <em>y</em> is <em>x</em> times 2 plus 12. (2x + 12) So, we know [x + y = x + (2x + 12)]. So let's solve.
x + y = x + (2x + 12)
102 = x + (2x + 12)
102 = 3x + 12
102 - 12 = 3x + 12 - 12
90 = 3x
90/3 = 3x/3
30 = x
The width is 30cm.
Time taken by Daniel to catch up with Frank is 4 minutes.
Step-by-step explanation:
The question is on relative speed; speed of a moving object with respect to another.
The two cars are travelling in the same direction at different speeds thus;
Relative speed = speed of Daniel - speed of Frank = 50-45= 5 mph
The time which the two meet = distance/ relative speed
Distance = 1/3 miles, which equals 0.33 miles
Time taken by Daniel to catch up with Frank is = 0.33/5 =0.066 hours = 4 minutes.
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Relative speed: brainly.com/question/10681729
Keywords: car, travelling, miles,started at the same point,catch up with
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