Another way is the formula:
Πr^2. (pi)(r) squared
Hope this helps!
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
A straight line (180o) is still an angle. Would you be wondering if the question said "Can 179o be a real angle?" No you would simply draw it. 1 degree more and you have 180o and it is an angle as well.
So you have a line that is both a line and an angle with A in the middle.
5,7
it aint even that hard bro
Answer:
Ameliorate retort, pertaining to preceding albeit contingent interrogate proximates subject to x = 12.
Step-by-step explanation:
Availing, exploiting, albeit maneuvering the Mathematic convention, Order of Operations (OO), the contiguous albeit proximate equation may ascertain as the preeminent imminent:
Groups: Not identified.
Exponents: Not identified, disparaging ₁.
Multiplication: Derived, pertaining to subtraction, 4 · (7/4x) = 4 · 21 <u>7x = 84</u>
Division: Derived, pertaining to multiplication, 7x = 84 ⇒ <em><u>x = 12</u></em>
Addition: Aggregate constants ⇒ 5/2x = 3/4x +21
Subtraction: Abate algebraic groups ⇒ 7/4x = 21
