What is the average rate of change of h over the interval −6 ≤ x ≤ 3? Give an exact number.
1 answer:
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<h3>Answer:</h3>
- C. (9x -1)(x +4) = 9x² +35x -4
- B. 480
- A. P(t) = 4(1.019)^t
Step-by-step explanation:
1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.
2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...
... (d+43) + d = 1003
... 2d = 960 . . . . . . . subtract 43
... d = 480 . . . . . . . . divide by 2
The second voyage lasted 480 days.
3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.
Since the starting value (in 1975) is 4 (billion), the population t years after that is ...
... P(t) = 4(1.019)^t
Answer:
Perimeter=48.497
Volume=997.661
Step-by-step explanation:
Perimeter:
Volume:
Answer:
Question 1) 17.4
Question 2) 1.7
Question 3) 2.8
Question 4) 8.6
Step-by-step explanation:
Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.
method to calculate Mean absolute deviation:
a. calculate mean
b. calculate absolute deviation of each data point
c. add all the deviations
d. divide absolute deviation by number of points
mean absolute deviation = ∑l-xl / n
The given problem has four sub-parts
Solution 1:
Mean= (78+99+90+80+55+56+102+88+60+42)/10
= 750/10
= 75
Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +
I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +
I 60-75 I + I 42-75 I) /10
= (174)/10
= 17.4
Solution 2:
Mean = (10+13+7+12+9+8+12+10+11+13)/10
= (105)/10
= 10.5
Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +
I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +
I 11-10.5 I + I 3-10.5 I) /10
= 17/10
= 1.7
Solution 3:
Mean= (1+7+10+5+3+3+6+12+9+4)/10
= 60/10
= 6
Mean absolute deviation = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +
I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10
= (28)/10
= 2.8
Solution 4:
Mean= (30+46+25+45+18+25+15+32+40+24)/10
= 300/10
= 30
Mean absolute deviation = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +
I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +
I 40-30 I + I 24-30 I) /10
= (86)/10
= 8.6
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