In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>
C is on the line and D is not on the line.
-1/2(-40)+1=21
-1/2(20)+1≠-11
Answer:
6
Step-by-step explanation:
(x^10)^3/5
=x^(10×3/5)
=x^6
(5rs-1t3)(-3r2st)
-30r^2s^2t+18rst^2
