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Doss [256]
3 years ago
7

2+2 equals? I am very stuck on this question

Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

2+2=4

Step-by-step explanation:

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Write the equation of the line
zysi [14]

-6 minus 6=0 i think it is correct

8 0
3 years ago
(235) a prime number
Llana [10]

Answer:

235 is not Prime. It’s Composite.

Step-by-step explanation:

Factors of 235:

1, 5, 47, 235.

1 x 235 = 235,

47 x 5 = 235.

Prime Numbers have the number 1 and the number it's self.

This number has 4 factors, which means it’s composite,

Composite Numbers have 3 or more factors.

4 0
3 years ago
Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antid
vredina [299]

Answer:

6t + \frac{t^2}{2}+2/5t^{5/2} + C

Step-by-step explanation:

Given the expression;

g(t) = 6 + t + t²/√t

This can be rewritten as;

g(t) = 6 + t +t²/t^1/2

g(t) = 6 + t +t^{2-1/2}

g(t) = 6 + t +t^3/2

Integrate the result

\int\limits {(6 + t+t^{3/2}}) \, dt\\

Using the formula x^{n+1}/n+1

\int\limits {(6  + t+t^{3/2}}) \, dt\\ = 6t + \frac{t^2}{2}+\frac{t^{3/2+1}}{3/2 + 1} \\ = 6t + \frac{t^2}{2}+\frac{t^{5/2}}{5/2} \\= 6t + \frac{t^2}{2}+2/5t^{5/2} + C

5 0
3 years ago
Write an equation of a line in the form y=mx+b that together with the equation x+3y=9 forms a linear system that has no solution
Alex73 [517]

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

7 0
3 years ago
Write an equation that is parallel to the line 2x - 3y = 9 and passes through the point (4, -1).
insens350 [35]

Answer: y = \frac{2x}{3} - \frac{11}{3}

Step-by-step explanation:

Equation of the line given ;

2x - 3y = 9

To find the slope of the line we will make y the subject of formula , that is

3y = 2x - 9

y = \frac{2x}{3}-3

Therefore ; the slope = \frac{2}{3}

Two lines are said to be parallel if they have the same slope

This means that the slope of the second line = \frac{2}{3}

Using the formula y-y_{1}= m ( x - x_{1} ) to find the equation of the line , we have

y - (-1 ) = \frac{2}{3} (x - 4 )

y + 1 = \frac{2x}{3} -\frac{2}{3}(4)

y + 1 = \frac{2x}{3} - \frac{8}{3}

y = \frac{2x}{3}-  \frac{8}{3}  - 1

y = \frac{2x}{3} - \frac{11}{3}

7 0
3 years ago
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