Answer:
1. at 1 hour, 3 miles is the distance.
2. at 0 hours, 0 miles is the distance.
3. at 3 hours, 9 miles is the distance.
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Answer: The boat moved 768.51 feet in that time .
Step-by-step explanation:
Since we have given that
Height of the lighthouse = 1000 feet
Angle depression to boat 'a' = 29°
Angle of depression to shore 'b' = 44°
Consider ΔABC,
Now, Consider, ΔABD,
We need to find the distance that the boat moved in that time i.e. BC
so,
Hence, the boat moved 768.51 feet in that time .
Letter A is the answer to your equation problem
Answer:
Step-by-step explanation: My variables are
d=big number q=small number
My equations are 6=3q2d+3=qI
will solve for q in first equation 6/3 = 3q/32=q
Now I will pluck back in to get d2d+3=(2) -3 -32d=-12d/2=-½d=-1/4 So the solution is(-1/4, .2)
