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Marina CMI [18]
3 years ago
11

Write an inequality, in slope-intercept form, for the graph below. If necessary,

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

Given:

The graph of an inequality.

To find:

The inequality in slope intercept form.

Solution:

The slope intercept form is:

y=mx+b

Where, m is slope and b is y-intercept.

From the given graph it is clear that the boundary line passes through the points (-3,0) and (0,-3).

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-0=\dfrac{-3-0}{0-(-3)}(x-(-3))

y=\dfrac{-3}{3}(x+3)

y=-1(x+3)

y=-x-3

From the given graph it is clear that the boundary line is a solid line and the shaded region lies above the line, so the sign of inequality must be "≥".

y\geq -x-3

Therefore, the required inequality is y\geq -x-3.

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A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

7 0
3 years ago
Solve the inequality graph the solution set and write it in interval notation x-6<5(x+2)
ANEK [815]

Answer:

x>-4

Step-by-step explanation:

x-6>5x+10

x-5x>10+6

-4x<16

x<16/-4

x<-4

3 0
3 years ago
50 POINTS I WILL MARK BRAINLIEST PLZ HELP ITS TIMED
oksano4ka [1.4K]

Answer:

The given polygon has 4 vertices and, 4 non-parallel and non equal sides. So the given polygon is a quadrilateral.

Step-by-step explanation:

The given vertices of are (–2, 4), (5, 4), (3, –3), and (–2, 0).

i found this on web

6 0
3 years ago
Read 2 more answers
A smoke jumper jumps from a plane that is 1700 ft above the ground. The function y = -16t2 + 1700 gives the jumper's height y in
lakkis [162]

Answer: (A) 6.6 sec (B) 6.89 sec

<u>Step-by-step explanation:</u>

    y    = -16t² + 1700

 1000 = -16t² + 1700

 <u>-1700</u>     <u>         -1700  </u>

  -700 = -16t²

 <u> ÷-16  </u>   <u>÷-16 </u>

 43.75 = t²

√43.75 = √t²

   6.6 = t

***********************************

    y    = -16t² + 1700

  940 = -16t² + 1700

 <u>-1700</u>     <u>         -1700  </u>

  -760 = -16t²

 <u> ÷-16  </u>   <u>÷-16 </u>

  47.5 = t²

√47.5 = √t²

  6.89 = t

4 0
3 years ago
Points W, K, and
Ksju [112]

Answer:

Points W, K, and J are collinear. Line CA and line YK intersect at point B. Point W is not contained on line m. The answers will be J,B,W

Step-by-step explanation:

Hope this helped :)

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