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Marina CMI [18]
3 years ago
11

Write an inequality, in slope-intercept form, for the graph below. If necessary,

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

Given:

The graph of an inequality.

To find:

The inequality in slope intercept form.

Solution:

The slope intercept form is:

y=mx+b

Where, m is slope and b is y-intercept.

From the given graph it is clear that the boundary line passes through the points (-3,0) and (0,-3).

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-0=\dfrac{-3-0}{0-(-3)}(x-(-3))

y=\dfrac{-3}{3}(x+3)

y=-1(x+3)

y=-x-3

From the given graph it is clear that the boundary line is a solid line and the shaded region lies above the line, so the sign of inequality must be "≥".

y\geq -x-3

Therefore, the required inequality is y\geq -x-3.

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An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is
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Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.

So, Y\sim Unif(1,5)

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

\text{Area under the density curve}=\text{length}\times \text{height}

                                          1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

P(Y

Thus, the 38th percentile is 2.52 seconds.

4 0
3 years ago
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