She has 25 nickels in the piggy bank
Let's raise i to various powers starting with 0,1,2,3...
i^0 = 1
i^1 = i
i^2 = ( sqrt(-1) )^2 = -1
i^3 = i^2*i = -1*i = -i
i^4 = (i^2)^2 = (-1)^2 = 1
i^5 = i^4*i = 1*i = i
i^6 = i^5*i = i*i = i^2 = -1
We see that the pattern repeats itself after 4 iterations. The four items to memorize are
i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i
It bounces back and forth between 1 and i, alternating in sign as well. This could be one way to memorize the pattern.
To figure out something like i^25, we simply divide the exponent 25 over 4 to get the remainder. In this case, the remainder of 25/4 is 1 since 24/4 = 6, and 25 is one higher than 24.
This means i^25 = i^1 = i
Likewise,
i^5689 = i^1 = i
because 5689/4 = 1422 remainder 1. The quotient doesn't play a role at all so you can ignore it entirely
Answer:
Hey there!
Our equation can be: 
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When y is 3, we could have 
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Let me know if this helps, or if you need more help :)
48%
Take 7 divided by all the rest added up
For this case we must find the product of the following expressions:
\frac {3x} {x + 1} * \frac {x} {x-7}
So:
\frac {3x ^ 2} {x ^ 2-7x + x-7} =\\\frac {3x ^ 2} {x ^ 2-6x-7}
So, we have to:
\frac {3x} {x + 1} * \frac {x} {x-7} = \frac {3x ^ 2} {x ^ 2-6x-7}
Answer:
\frac {3x ^ 2} {x ^ 2-6x-7}
Step-by-step explanation:
