1.) y+6=3(x+2) C
y+6=3x+6
y=3x+6-6
y=3x+6
2.) y=1/2(x+8)-2 B
y=1/2x+4-2
y=1/2x+2
3.) y+1=1(x-3) E
y+1=x-3
y=x-3-1
y=x-4
4.) -4x+y=-2 A
y=-4x-2
5.) 2x-4y=-4 F
-4y=-2x-4
y=-2/-4x-4/-4
y=2/4x+4/4
y=1/2x+1
6.) 2x+4y=8 D
4y=-2x+8
y=-2/4x+8/4
y=-1/2x+4/2
y=-1/2x+2
Whats the question tell me and i'll try to help
Answer:
is should be 11 hours hope it helps
Step-by-step explanation:
sorry if wrong people i didnt mean to tho
Answer:
r = 8,9,10
Step-by-step explanation:
The given inequality is :
5r≤6r−8 ...(1)
We need to find the value of r.
Subtracting 5r to both sides of the inequality .
5r-5r≤6r-5r−8
0≤r−8
r ≥ 8
Hence, the values of r are 8,9,10.
