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3 years ago

12

How do I solve this equation using long polynomial division?

1 answer:

gulaghasi [49]3 years ago

8 0

Oh okie oh gosh lol lol I don’t know

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How do you do this question?

bekas [8.4K]

<h3>Answer: 25/12</h3>

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Work Shown:

$\displaystyle S_n = \sum_{k=1}^{n} \frac{1}{k}\\\\\\\displaystyle S_4 = \sum_{k=1}^{4} \frac{1}{k}\\\\\\\displaystyle S_4 = \frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\\\displaystyle S_4 = \frac{12}{12}+\frac{6}{12}+\frac{4}{12}+\frac{3}{12}\\\\\\\displaystyle S_4 = \frac{12+6+4+3}{12}\\\\\\\displaystyle S_4 = \frac{25}{12}\\\\$

Note: in step 3, I'm adding terms in the form 1/k where k ranges from k = 1 to k = 4 (k being an integer)

5 0

3 years ago

WILL MARK THE BRAINIEST!!! HELP NEEDED

Citrus2011 [14]

Functions can be represented on graphs

The value of f(k + 3) is 0

Given that:

$\mathbf{f(-5) = k}$

From the graph, we have:

$\mathbf{f(-5) = 2}$

So, by comparison:

$\mathbf{k = 2}$

Substitute 2 for k in f(k + 3)

$\mathbf{f(k + 3) = f(2 +3)}$

$\mathbf{f(k + 3) = f(5)}$

From the graph, f(5) = 0

So, we have:

$\mathbf{f(k + 3) = 0}$

Hence, the value of f(k + 3) is 0

Read more about functions and graphs at:

brainly.com/question/1289308

4 0

3 years ago

Help with one last math question <br> thank u

Vitek1552 [10]

It has to be the last one, D. I did it over 3 times to make sure.

4 0

3 years ago

Find the area of each sector. Round your answers to the nearest tenth.

Orlov [11]

The answer is A.8.9.

3 0

3 years ago

Please help!<br><br> 1. n^6/n^2<br><br> a. 1/n^4<br> b. n^4<br> c. n^8<br> d. n12

Klio2033 [76]

Simplify the following:n^6/n^2
Combine powers. n^6/n^2 = n^(6 - 2):n^(6 - 2)
6 - 2 = 4:Answer: n^4 thus b: is you Answer

5 0

4 years ago