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Ira Lisetskai [31]
3 years ago
6

G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.

Mathematics
2 answers:
shtirl [24]3 years ago
6 0

BG ≅ AG

BG is the perpendicular to the side of the triangle while AG is the angle bisector , So BG cannot equal AG , So BG cannot be congruent to AG. Hence first is false.


DG ≅ FG

DG And FG both are the perpendicular to the sides from the incentre of the circle , Hence DG and FG are congruent , So second statement is true.


DG ≅ BG

Again DG and BG both are the perpendicular to the sides from the incentre of the circle , Hence DG and BG are congruent , So third statement is true.


GE bisects ∠DEF

As said in the question GE is the angle bisector , So yes GE bisects ∠DEF.

This Statement is true.


GA bisects ∠BAF

Again As said in the question GA is the angle bisector , So yes GA bisects ∠BAF.


Hence 2nd, 3rd , 4th , and 5th options are correct.

elena-s [515]3 years ago
4 0

Answer:

2,3,4,5 are the answers

Step-by-step explanation:


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kobusy [5.1K]

See attachement for the diagram of the triangle

Answer/Step-by-step explanation:

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