We have:
3x + 4y = 12
The first thing we should do in this case is clear and.
We have then:
4y = -3x + 12
y = (- 3x + 12) / (4)
Rewriting:
y = (- 3/4) x + 3
We evaluate now for x = 4
y = (- 3/4) (4) + 3
y = -3 + 3
y = 0
The ordered pair is:
(x, y) = (4, 0)
Answer:
y = (- 3/4) x + 3
(x, y) = (4, 0)
Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
You can write the question as a inequality.
c - 2 ≥ -22
add 2 on both sides...
c ≥ -20
Your answer is c ≥ -20.
