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vova2212 [387]
3 years ago
8

the altitude is drawn from the vertex angle of an isosceles triangle and is 15 cm long, if the base of the triangle is 16 cm lon

g, how long are the legs?
Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0
They are about 400cm long just make sure u put that
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A sociologist records the annual household income (in thousands of dollars) among a sample of families living in a high-crime ne
Gnoma [55]

Answer:

The lower quartile is Q_1=33 thousand dollars.

The median quartile is Q_2=39 thousand dollars.

The upper quartile is Q_3=45 thousand dollars.

Step-by-step explanation:

The lower quartile is the median value of the lower half of a data set at the 25th percentile of a distribution.

The median quartile is the median value of a data set at the 50th percentile of a distribution.

The upper quartile is the median value of the upper half of a data set at the 75th percentile of a distribution.

To locate each quartile in a data set, we follow four steps:

Step 1: Put the numbers in order: 23, 25, 33, 34, 39, 39, 44, 45, 48, 55

Step 2: The median is given by \frac{n+1}{2} where n is all scores in the data set.  

Because n = 10, the median position is \frac{10+1}{2}=5.5

The median is the average of the fifth and sixth positioned scores

Q_2=\frac{39+39}{2} =39

Step 3:  Compute \frac{n+1}{2} where n is all scores below Q_2.

For scores below Q_2, use only 23, 25, 33, 34, 39.

Because n = 5, the median position is \frac{5+1}{2}=3

The median is the third positioned score: Q_1=33

Step 4: Compute \frac{n+1}{2} where n is all scores above Q_2.

For scores above Q_2, use only  39, 44, 45, 48, 55

Because n = 5, the median position is \frac{5+1}{2}=3

The median is the third positioned score: Q_3=45

7 0
3 years ago
What is the solution to the equation 6x = 39?
SashulF [63]

Answer:

6.5

Step-by-step explanation:

39/6 comes out to 6.5

8 0
4 years ago
Which of the following inequalities are correct?
NARA [144]

Answer:

Only the First one, A is the correct answer. The other options such B and C are incorrect.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many 6 digit different locker combinations are possible if no repeat numbers are allowed?
Alex_Xolod [135]

Since we are trying to find the number of sequences can be made <em>without repetition</em>, we are going to use a combination.


The formula for combinations is:

_n C _k = \dfrac{n!}{k! (n - k)!}

  • n is the total number of elements in the set
  • k is the number of those elements you are desiring

Since there are 10 total digits, n = 10 in this scenario. Since we are choosing 6 digits of the 10 for our sequence, k = 6 in this scenario. Thus, we are trying to find _{10} C _6. This can be found as shown:

_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210


There are 210 total combinations.

7 0
3 years ago
Can someone help me?
Alexandra [31]
X=15, all you have to do is multiply
6 0
3 years ago
Read 2 more answers
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