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ki77a [65]
3 years ago
7

Guy's y'all plzz answer this who knows about it...and also exam is near​

Mathematics
1 answer:
Yanka [14]3 years ago
7 0

Answer:

Step-by-step explanation:

Okay so I will explain the first one.

2 to the power of 4 = 2x2x2x2

2 to the power of 6 = 2x2x2x2x2x2

2 to the power of 4 = 2x2x2x2

2^4 = 16

2^6 = 64

When you are multiplying powers you add.

+

When you subtract you takeaway.

-

So you would do

4+6+4

= 14

Meaning 2 to the power of 14

2x^{14}

So what is 2 to the power of 14.

You would do

2x2x2x2x2x2x2x2x2x2x2x2x2x2

The answer is 16384

You can also use a calculator

GOOD LUCK FOR YOUR TEST!

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Answer:

Q1.  2 - 5/ 8 - 0 = -3/8

Q2.  1- (-1)/6-2 = 2/4 simplified as 1/2

Q3.  (-5)- (-2)/ (-1)- (-3) = -3/2

Use a ruler to help you graph a line whose slope is 1/3. Label this line “a”

*Answer- 1/3 is being shown for rise/run (Rise over Run, 1 being rise and 3 being run). this means that you go up one and right 3.

Step-by-step explanation:

y2-y1 *over* x2- x1. Also if you can simplify the end fraction do it but if not then leav it as it is. This is the equation that I used for the first 3 problems. Also I didnt quit understand the 1st word problem sorry! I hope this helps :v

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Answer: I believe that A is the correct answer.

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Step-by-step explanation:

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3 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

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x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

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8. North point from the previous: By the 1st theorem,

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x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

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12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

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