Answer:
(-2, -18) and (2, 10)
Step-by-step explanation:
the answer is -18 and 10
Answer:
162, sorry if this is wrong
Step-by-step explanation:
so hmmm is compound interest, now, we'll be assuming the compounding period is per year, or annually, so it happens once per year.
![~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases} \\\\\\ A=5000\left(1+\frac{0.055}{1}\right)^{1\cdot 15}\implies A=5000(1.055)^{15}](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%5C%245000%5C%5C%20r%3Drate%5Cto%205.5%5C%25%5Cto%20%5Cfrac%7B5.5%7D%7B100%7D%5Cdotfill%20%260.055%5C%5C%20n%3D%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%20%5Ctextit%7Bannually%2C%20thus%20once%7D%20%5Cend%7Barray%7D%5Cdotfill%20%261%5C%5C%20t%3Dyears%5Cdotfill%20%2615%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D5000%5Cleft%281%2B%5Cfrac%7B0.055%7D%7B1%7D%5Cright%29%5E%7B1%5Ccdot%2015%7D%5Cimplies%20A%3D5000%281.055%29%5E%7B15%7D)
Answer:
d 0.50
Step-by-step explanation: hope it does help