All categories

3 years ago

Find the perimeter of the figure to the nearest hundredth. (includes picture)

Mathematics

1 answer:

mr_godi [17]3 years ago

4 0

Answer:

20+20+(circumference of a semi circle)

40+(1/2×2πr)

49+36

= 85mm

You might be interested in

Find the LCM for 10, 50, and 20

irinina [24]

Answer: The LCM is 100

Step-by-step explanation: source: trust me bro

8 0

2 years ago

Read 2 more answers

Iris charges a fee for her consulting services plus an hourly rate that is 11 times her fee. On a 7-hour job, Iris charged $470.

NemiM [27]

To answer this question, we let x be the the consulting fee of Iris. With this representation, the value for the hourly rate is equal to 11x. The equation that would allow us to relate the consulting services fee, hourly fee and total value given that she worked for 7 hours would then be equal to,
x + (7)(11x) = 470
Simplifying the left-hand side of the equation,
78x = 470
Dividing the equation by 78 will give us an answer of 6.

Hence,
 x = $6 (Consulting services fee)
 11x = 11($6) = $66 (hourly rate)

6 0

3 years ago

A bakery makes small batches of bread daily. Each day, the bakery records the amount of flour used the number of loaves of bread

miv72 [106K]

Answer:

The slope of the line would be the constant of proportionality for the line

shown. The point (35, 49) is really close the line which would make the

constant of proportionality 49/35 = 7/5. The equation of the line would be y =

7/5x. The number of loaves of bread from 85 pounds of flour would be

7/5(85) = 119 loaves.

Step-by-step explanation:

5 0

3 years ago

Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162

AnnZ [28]

Answer:

the answer is Y=(6/17)X + (285/17)

Step-by-step explanation:

1. Identify the X and Y coordinate of each point.

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

$m=\frac{33-21}{46-12}=\frac{12}{34}$ and then we simplify the result to $\frac{12}{34}$

3. Using the Point-slope equation which is Y-Y1=M(X-X1) we replace

$Y-33=\frac{6}{17}(X-46)$

$Y=\frac{6}{17}X-\frac{276}{17}+33$

$Y=\frac{6}{17}X+\frac{285}{17}$

7 0

3 years ago

find the lower quartile for the data {47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4}

mote1985 [20]

Answer:

The lower quartile is 23.4

Step-by-step explanation:

The given data are;

47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4

Rearranging the data, we have;

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4, 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

The lower quartile, Q₁, is the (n + 1)/4 th term which is (16 +1)/4 = 4.25th term

However since we have an even set of numbers, we place a separator at the middle and we look for the median of the left half as follows

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4║ 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

We have two numbers (17.4 + 29.4) at the median of the left set of numbers, we find the average of the two numbers to get the lower quartile

The lower quartile is therefore = (17.4 + 29.4)/2 = 23.4.

3 0

4 years ago