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Levart [38]
2 years ago
9

What is 63,020,000 in scientific notation

Mathematics
1 answer:
DiKsa [7]2 years ago
6 0

Answer:

6.302 x 10^{7}

Step-by-step explanation:

hope this helps! :D

have a miraculous day!! <3

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For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Pachacha [2.7K]
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13

Answer is option . D
5 0
2 years ago
What’s the error<br> 3+1(6/2)<br> 4(6/2)<br> 4(3)<br> 12
Mumz [18]
I think the error is that you did not divide 6 by 2 first because you are supposed to so you would get 3, then you do 1 times 3 which is 3, then you have 3 plus 3 left which would be 6. i’m hoping this is right and that it helps you
4 0
3 years ago
Read 2 more answers
Complete the equation of the line through<br> (-6, -5) and (-4,-4).<br> Use exact numbers.
Nutka1998 [239]

Answer:

y = \frac{1}{2} x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (- 4, - 4)

m = \frac{-4+5}{-4+6} = \frac{1}{2}, thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 6, - 5), then

- 5 = - 3 + c ⇒ c = - 5 + 3 = - 2

y = \frac{1}{2} x - 2 ← equation of line

7 0
2 years ago
What is the 5th term in the arithmetic sequence below?<br> 27, 15, 3.-9,-....
Lubov Fominskaja [6]

Answer: -21

Step-by-step explanation:

The numbers are subtracted by 12 each time

3 0
3 years ago
Write an equation in standard form for a line that passes through (4,1) &amp; (5,7)
tatuchka [14]
Y = mx + b

First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0

Set them equal to each other, 

m(4) + b - 1 = m(5) + b - 7

If you bring the b over to the left hand side it becomes

m(4) + b - b - 1 = m(5) - 7

m(4) - 1 = m(5) - 7

Solve for m

6 = m

Plug m = 6 into either equation from the beginning,

m(4) + b - 1 = 0

6(4) + b - 1 = 0

24 + b - 1 = 0

b = -23

Knowing m and b we can now make an equation

y = mx + b

y = 6x -23 Final answer



3 0
2 years ago
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