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Grace [21]
3 years ago
12

Which set of numbers only contains solutions to the inequality?

Mathematics
1 answer:
deff fn [24]3 years ago
3 0

Step-by-step explanation:

1. 3x>18

2. 3x/3>18/3

3. x>6

Now you can find the answer with the help of the graph below.

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Solve x in this equation 2x+8x=10x​
Over [174]
X= all real numbers.
any value of x makes this equation true
7 0
3 years ago
Read 2 more answers
The bottom of a 20-foot ladder is placed 4 ½ feet from the base of a house. To the nearest foot, at what height does the ladder
Oksanka [162]

Answer: 19 ft

Step-by-step explanation:

Hi, since the situation forms a right triangle (see attachment) we have to apply the Pythagorean Theorem:

c^2 = a^2 + b^2

Where c is the hypotenuse of the triangle (in this case the length of the ladder) and a and b are the other sides.

Replacing with the values given:

20^2 = (4 1/2)^2 + x^2

400=20.25 + x ^2

400-20.25 = x^2

379.75 = x^2

√379.75 = x

x = 19.48

x= 19 ft

Feel free to ask for more if needed or if you did not understand something.

6 0
4 years ago
Solve for the equation for the interval [0, 2pi). sec x/2 = cos x/2
Alenkinab [10]
Sec(x/2) = 1/cos(x/2)

sec(x/2)=cos(x/2) ----> cos^2(x/2)=1 ---> cos(x/2) = -1 and cos(x/2) = 1

Cos(x/2)=1 --- > x/2 = 0, only.  x = 0;

cos(x/2)=-1 ----> x/2 = pi -> x = 2pi. But the statement says [0,2pi), so 2pi can not be chosen.

Only x = 0.

In fact, your equation is equivalent to sec(x)=cos(x), for x in [ 0, pi), so yes, only x = 0 .
3 0
3 years ago
You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0
4 years ago
Find the area of the rectangle, to the nearest hundredth, with a base of 5 inches and a height = 2.5 inches.
Juli2301 [7.4K]
The equation for the area of a rectangle is: A = bh, where A = area, b = length of base, and h = height.

You're told that the base, b = 5 in, and the height, h = 2.5 in. Plug these numbers into the equation to find the area:
A = bh
A = (5)(2.5)
A = 12.5 in^2

If you include the hundredth place, your answer would be 12.50 in^2.

-------

Answer: 12.50 in^2



5 0
3 years ago
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