Answer:
1) The probability that the mean mpg for a random sample of 25 light vehicles is 0.042341.
2) between 20 and 25 --> 21-25/2.9 = -1.38
Step-by-step explanation:
Problem #1:
- Using the z-score formula, z = (x-μ)/σ/n, where x is the raw score = 20 mpg,μ is the population mean = 21 mpg , σ is the population standard deviation = 2.9, n = random number of samples.
<h3><u>X < 20</u></h3>
- = z = 20 - 21/2.9/√25
- = z = -1/2.9/5
- = z = -1.72414
<h2><u><em>Now</em></u></h2>
<em>P-value from Z-Table:</em>
<h3><u>P(x<20) = 0.042341</u></h3>
Problem #2:
<h3>21-25/2.9 = -1.38</h3>
P(A) =0.54
P(B)= 0.68
P'(A)= 1-0.54 = 0.46
P'(B)= 1- 0.68 = 0.32
The probability of neither of both event will occur:
= P'(A)×P'(B)
=0.46 × 0.32
=0.1472
Answer:
0.003
Step-by-step explanation:
By formula we know that:
z (x) = (x - m) / [sd / sqrt (n)]
where x is the value we want to know (60,000), m is the mean (63500), sd is the standard deviation (6100) and n is the sample size (35).
Replacing we have:
z (60000) = (60000 - 63500) / [6100 / sqrt (35)]
z = -3.39
If we look in the normal distribution table (attached), we have that the probability is 0.0003.
You have to plug in the numbers for x
Answer:
7 each
Step-by-step explanation:
28÷4=7
1/4 of 28=7