Hello!
In this problem, we will need to know our properties of exponents.
When we multiply two exponents, for example 10^3 × 10^-1, we will need to add the powers together. So, 10^3 × 10^-1 = 10^2 or 100.
With this, we can multiply the two constants together, and the exponents together to find our quotient.
(8.2 × 10^-6) × (9.4 × 10^-3) (rearrange the expression)
8.2 × 9.4 × 10^-6 × 10^-3 (multiply)
77.08 × 10^-9
If you wanted your answer to be in scientific notation, move the decimal place in 77.08 one place to the left, leaving you with 7.708 × 10^-8.
Therefore, your final answer is 7.708 × 10^-8.
If they are the sides then2x=x+26
2x-x=26
x=26
so each side =2*26=52
Sometimes the outlier, if it's too large, can throw off the mean, making it larger and smaller, so it isn't as accurate
sorry if this doesnt make sense if you need me to explain it more I will
Answer:
![Total = 11\frac{1}{8}\ cups](https://tex.z-dn.net/?f=Total%20%3D%2011%5Cfrac%7B1%7D%7B8%7D%5C%20cups)
Step-by-step explanation:
Given
See attachment for plot
Required
Total number of cups used
The number of dot on each dataset represent the number of student
So, to get the total number of cups, we simply add the product of the number of cups and the number of student for each data item
So, we have:
![Total = \frac{1}{8} * 6 + \frac{1}{4} * 5 + \frac{3}{8} * 2 + \frac{1}{2}*0 + \frac{5}{8} * 4 + \frac{3}{4} * 2 + \frac{7}{8} * 5](https://tex.z-dn.net/?f=Total%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20%2A%206%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%2A%205%20%2B%20%5Cfrac%7B3%7D%7B8%7D%20%2A%202%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A0%20%2B%20%5Cfrac%7B5%7D%7B8%7D%20%2A%204%20%2B%20%5Cfrac%7B3%7D%7B4%7D%20%2A%202%20%2B%20%5Cfrac%7B7%7D%7B8%7D%20%2A%205)
![Total = \frac{6}{8} + \frac{5}{4} + \frac{6}{8} + 0+ \frac{20}{8} + \frac{6}{4} + \frac{35}{8}](https://tex.z-dn.net/?f=Total%20%3D%20%5Cfrac%7B6%7D%7B8%7D%20%2B%20%5Cfrac%7B5%7D%7B4%7D%20%2B%20%5Cfrac%7B6%7D%7B8%7D%20%2B%200%2B%20%5Cfrac%7B20%7D%7B8%7D%20%2B%20%5Cfrac%7B6%7D%7B4%7D%20%2B%20%5Cfrac%7B35%7D%7B8%7D)
Solve
![Total = \frac{6+10+6+0+20+12+35}{8}](https://tex.z-dn.net/?f=Total%20%3D%20%5Cfrac%7B6%2B10%2B6%2B0%2B20%2B12%2B35%7D%7B8%7D)
![Total = \frac{89}{8}](https://tex.z-dn.net/?f=Total%20%3D%20%5Cfrac%7B89%7D%7B8%7D)
![Total = 11\frac{1}{8}\ cups](https://tex.z-dn.net/?f=Total%20%3D%2011%5Cfrac%7B1%7D%7B8%7D%5C%20cups)
Answer: 0.923
Step-by-step explanation:
Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves.
Pew Research Center finds that
P(A)=0.52 P(b)=0.26, and P(A or B)=0.54.
To find : P(A|B)
Since , ![\text{P(A or B)=P(A+P(B)-P(A and B)}](https://tex.z-dn.net/?f=%5Ctext%7BP%28A%20or%20B%29%3DP%28A%2BP%28B%29-P%28A%20and%20B%29%7D)
i.e. ![\text{P(A and B)=P(A)+P(B)-P(A or B)}](https://tex.z-dn.net/?f=%5Ctext%7BP%28A%20and%20B%29%3DP%28A%29%2BP%28B%29-P%28A%20or%20B%29%7D)
![\text{P(A and B)=}0.52+0.26-0.54=0.24](https://tex.z-dn.net/?f=%5Ctext%7BP%28A%20and%20B%29%3D%7D0.52%2B0.26-0.54%3D0.24)
Now, using conditional probability formula ,
![P(A|B)=\dfrac{\text{P(A and B)}}{\text{P(B)}}\\\\=\dfrac{0.24}{0.26}=0.923076923077\approx0.923](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cdfrac%7B%5Ctext%7BP%28A%20and%20B%29%7D%7D%7B%5Ctext%7BP%28B%29%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B0.24%7D%7B0.26%7D%3D0.923076923077%5Capprox0.923)
Hence, the conditional probability that an Internet user posts photos that they have taken themselves, given that they post videos that they have taken themselves = 0.923