Answer:
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and 
respectively.
Step-by-step explanation:
Given that,
For the first 9 holes X:
E(X) = 80
SD(X)=13
For the second 9 holes Y:
E(Y) = 80
SD(Y)=13
For the sum W=X+Y, the following properties holds for means , variance and standard deviation :
E(W)=E(X)+E(Y)
and
V(W)=V(X)+V(Y)
⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]
∴E(W)=E(X)+E(Y) = 80 +80=160
and
∴
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and respectively.
Y = 3x + 4 is the equation
Put the first equation in slope-intercept form, or y = mx + b. Start by subtracting y from both sides.
2x - y = -10, subtract 2x from both sides.
-y = -10 - 2x
Divide both sides by negative one.
y = 10 + 2x
To find the slope when the equations are in slope-intercept form you look at the coefficient of x. The first equation has the slope of 2 (which we just found), and the second equation has the slope of -2.
Parallel lines have the same slope and perpendicular lines have opposite reciprocal slopes. Since 2 and -2 are neither of these, your answer is neither.
We have a pair of vertical angles here. So they would equal each other.
3x+50=6x-10
Subtract 3x to 6x:
50=3x-10
Add 10 to 50:
60=3x
Divide 3 to both sides:
x=30
Answer:
So angle 3 is congruent to angle 4 because they are both complimentary to 1 and 2.
By SAS, triangle SNM is congruent to triangle SNF.
By CPCTC, angle QMN is congruent to angle RFN.
By AAS, triangle QMN is congruent to RNF.
So by CPCTC, QM=RP
