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2 years ago

Find the range y=4-x domain =-2,3,5

Mathematics

1 answer:

Wittaler [7]2 years ago

6 0

Answer:

range: {6, 1, -1}

Step-by-step explanation:

y = 4-x

when x = -2, y = 6

when x = 3, y = 1

when x = 5, y = -1

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What is the value of x in the equation 3 = 2x? A. 2/3

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3 divided by 2 is 1.5 so c

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2 years ago

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Which equation is represented by the graph below?

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3 years ago

Choose the smallest fraction? 3/4 1/5 3/10 1/7

Evgesh-ka [11]

Answer:

Hey there!

3/4= 0.75

1/5=0.2

3/10=0.3

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Thus, 1/7 is the smallest fraction.

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2 years ago

Of 340 male and 270 female employees at the home office of Gibraltar Insurance Company, 170 of the men and 180 of the women are

sineoko [7]

Answer:

The correct answer is 0.486.

Step-by-step explanation:

Total number of employees at the home office of Gibraltar Insurance Company is 270 + 340 = 610

Number of employees on flex time are 350, out of which 170 are men and 180 are women.

We need to find the probability that out of the given employees, a randomly chosen one is on flex time and is a man.

Favorable outcomes are 170 and total outcome is 350.

Thus the probability is given by $\frac{170}{350}$ = 0.4857≈ 0.486

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3 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

Find the range y=4-x domain =-2,3,5​

Find the range y=4-x domain =-2,3,5