9514 1404 393
Answer:
f^-1(x) = 4+∛((x-6)/5)
Step-by-step explanation:
To find the inverse function, solve ...
x = f(y)
then write the answer in functional form.
![\displaystyle x=f(y)\\\\x=5(y-4)^3+6\\\\x-6=5(y-4)^3\\\\\frac{x-6}{5}=(y-4)^3\\\\\sqrt[3]{\frac{x-6}{5}}=y-4\\\\y=4+\sqrt[3]{\frac{x-6}{5}}\\\\\boxed{f^{-1}(x)=4+\sqrt[3]{\frac{x-6}{5}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Df%28y%29%5C%5C%5C%5Cx%3D5%28y-4%29%5E3%2B6%5C%5C%5C%5Cx-6%3D5%28y-4%29%5E3%5C%5C%5C%5C%5Cfrac%7Bx-6%7D%7B5%7D%3D%28y-4%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%3Dy-4%5C%5C%5C%5Cy%3D4%2B%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%5C%5C%5C%5C%5Cboxed%7Bf%5E%7B-1%7D%28x%29%3D4%2B%5Csqrt%5B3%5D%7B%5Cfrac%7Bx-6%7D%7B5%7D%7D%7D)
__
The graph shows the function and its inverse to be reflections of each other in the line y=x, as they should be.
Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
Radical form for 112 would be 4{7 and then I think you can just search up how to reduce the 4 to 7 i don’t have the symbol btw
Answer:
The rule that represents the function is
therefore the function is 
Step-by-step explanation:
We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>
Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.
<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.
So <u>we propose the rule </u>
<u> which is correct for the first 3 values of x.</u>
Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as


Therefore, the rule is correct, and the function is
