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Pie
3 years ago
6

X+17.4=23.5 ??????????

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Answer:

It depends what your asking, if you do the problem your full answer is 409 because your muplitying tand then finding the sum before Equally the answer so that's what could find. I really hope this helps you out.

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What is the number of solid 3-inch by 2-inch by 2-inch rectangular prisms that can be
Lerok [7]

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It will be about 12 inches

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4 years ago
What is the exact circumference of a circle with a radius of 15 cm?
murzikaleks [220]

I hope this helps you

Circumference=2. pi. r

C=2.pi.15

C=30.pi

6 0
3 years ago
The graph of a certain quadratic function has no x-intercepts. Which of the following are possible values for the discriminant?
Savatey [412]

Answer:

c

Step-by-step explanation:

the graph has no side value, therefore the answer is 0

4 0
3 years ago
If 3 notebooks cost $3.51, how much would 7 notebooks cost?
Ket [755]
Well, you would first divide 3÷ 3.15 Do you know what that would give you?
8 0
4 years ago
Read 2 more answers
Three potential employees took an aptitude test. each person took a different version of the test. the scores are reported below
timama [110]

Answer:

Vincent and Reyna.

Step-by-step explanation:

As z-score indicates that a data point is how many standard deviation above mean, so to find which of three applicant should be offered the job, let us find the z-score for each person using z-score formula.

z=\frac{x-\mu}{\sigma}, where,

z= z-score,

x= Random sample score,

\mu= Mean,

\sigma= Standard deviation.

\text{z-score for Vincent}=\frac{83.5-68.2}{9}

\text{z-score for Vincent}=\frac{15.3}{9}

\text{z-score for Vincent}=1.7

Therefore, Vincent's score on aptitude test is 1.7 standard deviation above mean.

\text{z-score for Kaitlyn}=\frac{251.2-238}{22}

\text{z-score for Kaitlyn}=\frac{13.2}{22}

\text{z-score for Kaitlyn}=0.6

Therefore, Kaitlyn's score on aptitude test is 0.6 standard deviation above mean.

\text{z-score for Reyna}=\frac{8.04-7.2}{0.7}

\text{z-score for Reyna}=\frac{0.84}{0.7}

\text{z-score for Reyna}=1.2

Therefore, Reyna's score on aptitude test is 1.2 standard deviation above mean.

Since Vincent and Reyna has higher z-scores, therefore, they are further above mean than Kaitlyn. Therefore, Vincent and Reyna should be offered the job.

7 0
3 years ago
Read 2 more answers
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