Answer:
D. ![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Step-by-step explanation:
![\sqrt[3]{9x^3y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9x%5E3y%5E4%7D)
![\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%5Csqrt%5B3%5D%7Bx%5E3%7D%5Csqrt%5B3%5D%7By%5E4%7D)
The ![\sqrt[3]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D)
cancels out to become x:
![\sqrt[3]{9}x\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E4%7D)
Split the 
![\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E3%7D%5Csqrt%5B3%5D%7By%5E1%7D)
![\sqrt[3]{y^3} =y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E3%7D%20%3Dy)
![xy\sqrt[3]{9} \sqrt[3]{y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9%7D%20%5Csqrt%5B3%5D%7By%7D)
Put the cube root of y and cube root of 9 together:
You only need to know one side, you can use , tan, sin, or cos of the angles to find the other 2 sides.
Answer:
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
If 2 lines are perpendicular then the product of their slopes = - 1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x - 4 ← is in slope- intercept form
with slope m = - 1
5x - 5y = 20 ( subtract 5x from both sides )
- 5y = - 5x + 20 ( divide all terms by - 5 )
y = x - 4 ← in slope- intercept form
with slope m = 1
Thus product of their slopes is - 1 × 1 = - 1
Therefore the lines are perpendicular
Answer:
½(x+y) - y/3. Hope this helps! If not, sorry!
Step-by-step explanation:
