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ololo11 [35]
3 years ago
9

as a laboratory assistant you measure chemicals using the metric system for your car in the resources you need to measure out 45

grams of sodium chloride the volume on using this the mall in ounces about how many ounces of sodium chloride would you need​
Mathematics
2 answers:
IceJOKER [234]3 years ago
6 0

235 ounces atleast..... i believe

stiv31 [10]3 years ago
4 0

Answer: 1.587 ounces

Step-by-step explanation:

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If f(x) = x2 + 1 and g(x) = x - 4, which value is equivalent to (fºg)(10)?
jolli1 [7]

Answer:

2x - 3..... 2*10 - 3 = 17

Step-by-step explanation:

Fog) = g(fx)) = f(x) - 4 => 2x - 3

6 0
3 years ago
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What is the answer it's not factor
Helen [10]
It is a divisor
hope this helps

7 0
3 years ago
112 is 70% of _______
aliina [53]

Answer:

160

Step-by-step explanation:

70% of 160=112.

A handy trick is to divide the number by the percentage.

Brainliest please I need those points.

8 0
3 years ago
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31. A business rents cars for $150 a day and vans for $300 a day. One day it rented a total of 30 vehicles and
Advocard [28]

Answer:

D. 22 Cars and 8 Vans

Step-by-step explanation:

1. You multiply 22 x 150 = 3,300.

2. Then you multiply 300 x 8 = 2,400.

3. Next, add 3,300 + 2,400

4. That equals 5700.

Hopefully, that helps!

7 0
3 years ago
Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0
3 years ago
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